in reply to Comparing hash values against other hash values

You might consider the following:

use strict; use warnings; my %components = ( COMP1 => { eth1 => "10.172.9.21/24", eth1_gw => "10.172.1.1", eth2 => "10.172.10.21/24", }, COMP2 => { eth1 => "10.172.9.22/24", eth2 => "10.172.11.21/24", }, COMP3 => { eth1 => "10.172.11.21/24", eth2 => "10.172.13.21/24", eth3 => "10.173.2.98/24", }, ); my @components = keys %components; while ( @components > 1 ) { my $comp = shift @components; foreach my $a ( values %{$components{$comp}} ) { foreach my $b ( map { ( values %{$components{$_}} ) } @compone +nts ) { compare( $a, $b ); } } } sub compare { my ( $a, $b ) = @_; print "$a compared with $b\n"; }

Or it might be more effective to reorganize your data:

use strict; use warnings; my %components = ( COMP1 => { eth1 => "10.172.9.21/24", eth1_gw => "10.172.1.1", eth2 => "10.172.10.21/24", }, COMP2 => { eth1 => "10.172.9.22/24", eth2 => "10.172.11.21/24", }, COMP3 => { eth1 => "10.172.11.21/24", eth2 => "10.172.13.21/24", eth3 => "10.173.2.98/24", }, ); my %addresses; foreach my $comp ( keys %components ) { foreach my $eth ( keys %{$components{$comp}} ) { push(@{$addresses{$components{$comp}{$eth}}}, "$comp:$eth"); } } foreach my $address ( keys %addresses ) { print "$address: appears on " . join (', ', @{$addresses{$address} +}) . "\n"; }

The latter doesn't compare the addresses but it does let you easily identify which components have interfaces with the same address.