Re: Control characters

I was going to suggest using regular expressions and the s/// command but the control characters make it rather tricky, since the ^ anchors a search at the beginning of a string. Quick and dirty, but maybe something like this?

s/(.)?^O/\1/g; s/(.)?^N/\1/g;

--
tbone1, YAPS (Yet Another Perl Schlub)
And remember, if he succeeds, so what.
- Chick McGee

Comment on Re: Control characters

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Re^2: Control characters by AnomalousMonk (Archbishop) on Jun 05, 2009 at 16:55 UTC
`s/(.)?^O/\1/g; s/(.)?^N/\1/g;` [download] But what do these statements really do? `>perl -wMstrict -le "for my $str (@ARGV) { printf q{%s -> }, $str; $str =~ s/(.)?^O/\1/g; $str =~ s/(.)?^N/\1/g; print $str; } " OhNoOhNo NotOnNotOn \1 better written as $1 at -e line 1. \1 better written as $1 at -e line 1. Use of uninitialized value $1 in substitution iterator at -e line 1. OhNoOhNo -> hNoOhNo Use of uninitialized value $1 in substitution iterator at -e line 1. NotOnNotOn -> otOnNotOn` [download]	[reply] [d/l] [select]

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Re^2: Control characters
by AnomalousMonk (Archbishop) on Jun 05, 2009 at 16:55 UTC

s/(.)?^O/\1/g; s/(.)?^N/\1/g;
[download]

>perl -wMstrict -le
"for my $str (@ARGV) {
   printf q{%s -> }, $str;
   $str =~ s/(.)?^O/\1/g;
   $str =~ s/(.)?^N/\1/g;
   print $str;
   }
"  OhNoOhNo  NotOnNotOn
\1 better written as $1 at -e line 1.
\1 better written as $1 at -e line 1.
Use of uninitialized value $1 in substitution iterator at -e line 1.
OhNoOhNo -> hNoOhNo
Use of uninitialized value $1 in substitution iterator at -e line 1.
NotOnNotOn -> otOnNotOn
[download]

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