in reply to if modifier of a print statement
So I changed the first print line to
print ($_ . "\n") && next if /no_proc/;
This gives the output I want, but also the note
print (...) interpreted as function at ...
You get that warning message because of the space between print and the left parenthesis. If you had written it as
print($_ . "\n") && next if /no_proc/;
you would not get a warning.
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