Re^2: segmentation fault for perl

I am invoking the script x.pl from y.pl as system(x.pl); my $exit_status = $? >> 8; I am capturing the status always. It sometimes happen that x.pl is able to execute successfuly (it updates a database before exiting). But capturing the error status in y.pl shows the system(x.pl) has a exit status of segmentation fault. My os is solaris 10

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Re^3: segmentation fault for perl by rovf (Priest) on Jul 07, 2009 at 09:23 UTC
I am invoking the script x.pl from y.pl as system(x.pl); I take it to mean `system('x.pl');`. And I guess you made sure that x.pl has a correct #! line? `my $exit_status = $? >> 8;` I am capturing the status always. How do you know that your program died by segmentation fault? `$? >> 8` is whatever x.pl passes to its `exit` call, so from this value alone, you can not deduce that your program segfaulted. But if it does, it could be that either the Perl used has a problem (that's why I'm asking you about the #! line), or (more likely) that x.pl uses some Perl module which contains compiled parts, so this would be the place to look. -- Ronald Fischer <ynnor@mm.st>	[reply] [d/l] [select]

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Re^3: segmentation fault for perl
by rovf (Priest) on Jul 07, 2009 at 09:23 UTC

I am invoking the script x.pl from y.pl as system(x.pl);

I take it to mean system('x.pl');. And I guess you made sure that x.pl has a correct #! line?

my $exit_status = $? >> 8; I am capturing the status always.

$? >> 8

exit

But *if* it does, it could be that either the Perl used has a problem (that's why I'm asking you about the #! line), or (more likely) that x.pl uses some Perl module which contains compiled parts, so this would be the place to look.

--
Ronald Fischer <ynnor@mm.st>

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