in reply to Re: two regexes in one function call
in thread two regexes in one function call
That's not the problem. For starters, neither s/// modify the variable.
There's problems with that quote anyway. Perl *does* define the operand evaluation order for some operators (namely the comma and the logical operators), it's regularly relied upon for some other operators (assignment operators and method call), and it's predictable for the rest.
Update: Added second paragraph.
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