I get that annoying "use of uninitialized value of $1 and $2 in concatenation(.) or string at my print $out statement line. Should I be concerned about that?

If you are asking this question, that means there is something that you do not understand about your code. Yes, you should be concerned, and yes, you should try to determine the root cause of the warning.

As an aside, you should always check the results of each open and opendir:

opendir my $dh, $dir or "Can not open directory $dir: $!";
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