Re: Too lazy to be lazy

I think it is because @_ is magic

my @foo = 1 .. 2;
sub modit { $_[0] .= ' magic ' }
print modit(@foo),"\n";
print "@foo\n";
__END__
1 magic
1 magic  2
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Comment on Re: Too lazy to be lazy Download Code

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Re^2: Too lazy to be lazy by JadeNB (Chaplain) on Jul 29, 2009 at 20:46 UTC
I know about, and am relying on, the aliasing semantics of function calls and `@_`. What was confusing me was why, in what seemed to be otherwise identical code, `$a` was capturing an alias inside the nested subroutine, but `$_` was not.	[reply] [d/l] [select]