in reply to Re^2: split and assign
in thread split and assign
Although it must be admitted that this approach would get a bit tedious if one were interested not in the second field but in the twenty-second!I hoped for a mad moment that
or at leastmy ( ( undef ) x 21, $var ) = func;
would work—but they don't ….( ( undef ) x 21, my $var ) = func;
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