in reply to Re^4: Local for lexicals
in thread Local for lexicals

Maybe this is a repetition of a question already asked--possibly even asked and answered--but having re-read the thread, I cannot see it. So here goes: 

{ #outer scope
  $lamb = lambda ( $x, $y, $z ) => sub { $x + $y }
}

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This is, in a sense, the crux of my problem—I don't want the values of $x, $y, and $z to leak from the inside out, or vice versa,

What are you trying to achieve that this doesn't? 

my( $x, $y, $z ) = ( 1,2,3 );
my $lamb = do{
    my( $x, $y, $z ) = ( $x, $y, $z );
    lambda ( $x, $y, $z ) => sub { $x + $y }
}

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Re^6: Local for lexicals
by JadeNB (Chaplain) on Aug 12, 2009 at 19:17 UTC
    What are you trying to achieve that this doesn't? 
    my( $x, $y, $z ) = ( 1,2,3 );
my $lamb = do{
    my( $x, $y, $z ) = ( $x, $y, $z );
    lambda ( $x, $y, $z ) => sub { $x + $y }
}

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    Unfortunately, I don't know quite what this does, so I can't answer! My question (at least, the part of my question that seems to have attracted the most attention) is how to write lambda in such a way that lambda( $x, $y, $z ) => sub { $x + $y } is the same as sub { $_[0] + $_[1] }. As far as I can tell, the code that you've written would be the same as 
    my ( $x, $y, $z ) = ( 1, 2, 3 );
lambda ( 1, 2, 3 ) => sub { 1 + 2 }

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