cmv has asked for the wisdom of the Perl Monks concerning the following question:
Running the following ssh command locally:
ssh user@host tail -f /etc/passwd
Results in the following 2 processes on the far end machine (note PGID & SID):
UID PID PPID PGID SID CMD root 22409 4763 4763 4763 sshd -f /etc/ssh/sshd_config -R user 22411 22409 22411 22411 tail -f /etc/passwd
As expected, when I ctrl-c out of the ssh command on the originating local computer, I loose the sshd_config process at the far end, but the tail -f child process survives and looks like this:
UID PID PPID PGID SID CMD user 22411 1 22411 22411 tail -f /etc/passwd
I would like for the child process to die when I ctrl-c out of the ssh command. How can I do this?
Put another way, how can I get the child process (tail -f) to be in the same process group as the parent (sshd_config)?
My first thought was to use perl's setpgrp command: setpgrp(PID, PGRP) where:
PID - Child's process ID PGRP - Parents process group
However, this seems to always fail on SunOS. Probably because of what is described in the setpgrp camel book description:
Sets the current process group for the specified PID, 0 for the current process. Will produce a fatal error if used on a machine that doesn't implement POSIX setpgid(2) or BSD setpgrp(2). If the arguments are omitted, it defaults to 0,0 . Note that the BSD 4.2 version of setpgrp does not accept any arguments, so only setpgrp(0,0) is portable. See also POSIX::setsid() .
Any help is appreciated.
Thanks!
-Craig
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Re: Unwanted SSH child survives after ssh session
by almut (Canon) on Aug 11, 2009 at 21:05 UTC | |
by cmv (Chaplain) on Aug 12, 2009 at 13:45 UTC |