Re: If condition logic yielding partially correct output

in reply to If condition logic yielding partially correct output

Take a look at What is true and false in Perl. The string 'test' (being not equal to an empty string) passes your first clause; and since the string 'test' is not equal to the string '0', in numeric context, it passes the second clause. Since 1 && 1 evaluate to 1, 'test' satisfies your if condition.

Update -- clarified that we are talking about strings in the second clause

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Comment on Re: If condition logic yielding partially correct output

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Re^2: If condition logic yielding partially correct output by dsheroh (Monsignor) on Aug 13, 2009 at 11:27 UTC
Erm... "test" is equal to 0 in numeric context, so `if (($key ne "") && ($key != 0))` evaluates as false for "test" (`"test" ne ""` is true, `"test" != 0` is false; true && false = false), which is why the `print` after the `if` doesn't execute.	[reply] [d/l] [select]
Re^2: If condition logic yielding partially correct output by Anonymous Monk on Aug 13, 2009 at 11:12 UTC
What is true and false in Perl?	[reply]

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