Re^2: accessing hash of arrays

I understood. we can print that by loop. But I want to access like an array. I wanted to sort those numbers. For this I can store all these numbers and I can pass. But I want to pass all those numbers to sort without storing.

Comment on Re^2: accessing hash of arrays

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Re^3: accessing hash of arrays by rovf (Priest) on Aug 21, 2009 at 08:20 UTC
my %hash = ( 4 => 10, "mango" , 2 => 04, "banana" , 3 => 20, "apple" ); You use values to turn your hash into an array of array references. Then you use map to turn this array into an list of the numbers. Finally you use sort to sort that list. -- Ronald Fischer <ynnor@mm.st>	[reply] [d/l]