Re^3: is (?: ... ) capturing

Yes, because lookbehind has to be fixed-width, you'd need to do s/(\s+)\w/${1}_/g.

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Re^4: is (?: ... ) capturing by ikegami (Patriarch) on Sep 07, 2009 at 09:30 UTC
`s/(\s+)\w/${1}_/g` [download] simplifies to `s/(\s)\w/${1}_/g` [download] Now you can use a zero-width lookbehind to get the speed boost of avoiding captures. `s/(?<=\s)\w/_/g` [download] Or in 5.10+: `s/\s\K\w/_/g` [download]	[reply] [d/l] [select]
Re^5: is (?: ... ) capturing by ysth (Canon) on Sep 07, 2009 at 17:18 UTC
Good point, I wasn't thinking. My answer would only apply with something like /\S\s+\w/. -- A math joke: r = \| \|csc(θ)\|+\|sec(θ)\|-\|\|csc(θ)\|-\|sec(θ)\|\| \| Online Fortune Cookie Search Office Space merchandise	[reply]
Re^4: is (?: ... ) capturing by jeanluca (Deacon) on Sep 07, 2009 at 07:51 UTC
ok, thnx again!!	[reply]