in reply to Re^2: [emacs] converting perl regex into elisp regex
in thread [emacs] converting perl regex into elisp regex
/usr/bin/perl -w /tmp/plre2el.pl Perlcode: "(.*?)" Elispcode: \"\\(.*?\\)\"
use strict; use warnings; # version 0.2 $\="\n"; #--- flags my $flag_interactive; # true => no extra escaping of backslashes my $RE='\w*(a|b|c)\d\('; $RE='\d{2,3}'; $RE='"(.*?)"'; print "Perlcode: $RE"; #--- hide pairs of backslashes $RE=~s#\\\\#\0#g; # TODO check for suitable long "hidesequence" instead of a simple \0 #--- TODO normalisation of needless escaping # e.g. from /\"/ to /"/, since it's no difference in perl but might +confuse elisp #--- toggle escaping of 'backslash constructs' my $bsc='(){}|'; $RE=~s#[$bsc]#\\$&#g; # escape them once $RE=~s#\\\\##g; # and erase double-escaping #--- replace character classes my %charclass=( w => 'word' , # TODO: emacs22 already knows \w ??? d => 'digit', s => 'space' ); my $kc=join "|",keys %charclass; $RE=~s#\\($kc)#[[:$charclass{$1}:]]#g; #--- unhide pairs of backslashes $RE=~s#\0#\\\\#g; #--- escaping for elisp string unless ($flag_interactive){ $RE=~s#\\#\\\\#g; # ... backslashes $RE=~s#"#\\"#g; # ... quotes } print "Elispcode: $RE";
Cheers Rolf
Please note: xemacs knows "Raw Strings" where escaping is not neccessary, but I doubt that normal Perl RE syntax can be used from within Gnu Emacs Lisp because of the quoting problem, so the conversion can in general only be done with perl!
UPDATE:
-TODO: Just noticed that i still need a special treatment for escape sequences like \t and \n. I'll add this tomorrow.
last version re_pl2el.pl
use strict; use warnings; # version 0.3 $\="\n"; # TODO # * wrap converter to function # * testsuite #--- flags my $flag_interactive; # true => no extra escaping of backslashes my $RE='\w*(a|b|c)\d\('; $RE='\d{2,3}'; $RE='"(.*?)"'; $RE="\0".'\"\t(.*?)"'; print "Perlcode:\t $RE"; #--- encode all \0 chars as escape sequence $RE=~s#\0#\\0#g; #--- substitute pairs of backslashes with \0 $RE=~s#\\\\#\0#g; #--- hide escape sequences of \t,\n,... with # corresponding ascii code my %ascii=( t =>"\t", n=> "\n" ); my $kascii=join "|",keys %ascii; $RE=~s#\\($kascii)#$ascii{$1}#g; #--- normalize needless escaping # e.g. from /\"/ to /"/, since it's no difference in perl # but might confuse elisp $RE=~s#\\"#"#g; #--- toggle escaping of 'backslash constructs' my $bsc='(){}|'; $RE=~s#[$bsc]#\\$&#g; # escape them once $RE=~s#\\\\##g; # and erase double-escaping #--- replace character classes my %charclass=( w => 'word' , # TODO: emacs22 already knows \w ??? d => 'digit', s => 'space' ); my $kc=join "|",keys %charclass; $RE=~s#\\($kc)#[[:$charclass{$1}:]]#g; #--- unhide pairs of backslashes $RE=~s#\0#\\\\#g; #--- escaping for elisp string unless ($flag_interactive){ $RE=~s#\\#\\\\#g; # ... backslashes $RE=~s#"#\\"#g; # ... quotes } #--- unhide escape sequences of \t,\n,... my %rascii= reverse %ascii; my $vascii=join "|",keys %rascii; $RE=~s#($vascii)#\\$rascii{$1}#g; print "Elispcode:\t $RE"; #TODO whats the elisp syntax for \0 ???
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Re^4: [emacs] converting perl regex into elisp regex
by u65 (Chaplain) on Jul 27, 2016 at 15:08 UTC | |
by LanX (Saint) on Jul 27, 2016 at 15:40 UTC |