in reply to Comma Operator, BUG or feature ???

use 
use Data::Dumper;
$Data::Dumper::Useqq = 1;
...

[download]

To properly escape non-printing characters in the output.

See the documentation for $; to see what's happening.

Perl 6 - links to (nearly) everything that is Perl 6.

Replies are listed 'Best First'.
Re^2: Comma Operator, BUG or feature ???
by nif (Sexton) on Sep 22, 2009 at 16:21 UTC
    Thank you for the explanation - I didn't know that $foo{$a,$b,$c} means $foo{join($;, $a, $b, $c)} Thank you again
[reply]

In Section Seekers of Perl Wisdom