in reply to How to replace in one regexp
I want to get $path from $target. How I do it in one regexp?Those are two different questions, and are likely to have different answers. I would leave it as is, but if you insist on using one regexp, I guess (haven't tried it), something like:# How to optimize?
$path =~ s/(?:[^/]*\?.*$)|(?:[^/]+$)/;
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