Re^4: Perl 5.11.0 now available

I don't think that it really is.

Why not? How does "treated like any vulgar scalar" differ from "no longer treated specially"? (I said phrase, not sentence)

A commutativity breakage means that there are some circumstances in which the smart match depends on order, not that the smart match is always completely determined by the right-hand member.

I know. I never said otherwise.

Comment on Re^4: Perl 5.11.0 now available

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Re^5: Perl 5.11.0 now available by JadeNB (Chaplain) on Oct 03, 2009 at 21:32 UTC
How does "treated like any vulgar scalar" differ from "no longer treated specially"? Sorry, you're right—aside from the fact that the former is funny and the latter isn't, not at all. :-) I remembered only “commutativity breakage” and “vulgar scalar”, and completely forgot about the bit in between: code references are no longer treated specially when appearing on the left of the `~~` operator so that I didn't realise what it was that you were claiming was redundant.	[reply] [d/l]

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Re^5: Perl 5.11.0 now available
by JadeNB (Chaplain) on Oct 03, 2009 at 21:32 UTC

How does "treated like any vulgar scalar" differ from "no longer treated specially"?

I remembered only “commutativity breakage” and “vulgar scalar”, and completely forgot about the bit in between:

code references are no longer treated specially when appearing on the left of the ~~ operator

[reply]
[d/l]