Re: using shift and $

( And I mean, seriously... where the #$!@& is shift output going?? Is its scope only in () ??? )

Actually, it's scope is the whole while loop. For instance..

for my $foo (@wibble) {
   print $foo;
}
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Oh, and $_ is global, as mentioned above (said Pileofrog as though he already knew that...) so the scope won't matter.

UpdateD'oh! Removed stupid '=' sign. Thanks moritz.

Comment on Re: using shift and $_ in loop Download Code

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Re^2: using shift and $_ in loop by Anonymous Monk on Oct 22, 2009 at 14:10 UTC
... so the scope won't matter. Famous last words :-)	[reply]