Re: Using grep on windows

Your regexp "^CNR[0-9]" can never match as-is since you'll never have a beginning-of-line immediately following a ". You probably want to either drop the quotes (if the token always begins at the beginning of a line), or drop the caret (if the token always occurs in quotes). Not to mention \d is more concise than [0-9]

Update: Pedantry about [0-9] vice \d noted; suggestion withdrawn.

The cake is a lie.
The cake is a lie.
The cake is a lie.

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Re^2: Using grep on windows by JavaFan (Canon) on Oct 27, 2009 at 17:20 UTC
Not to mention `\d` is more concise than `[0-9]` And `.` is even more concise. `\d` and `[0-9]` are not equivalent. The latter matches 10 characters, the former several hundreds.	[reply] [d/l] [select]
Re^3: Using grep on windows by ikegami (Patriarch) on Oct 27, 2009 at 17:42 UTC
In general, yes, \d can match many more than 10 characters. In the above program, no. Even if it did, it wouldn't be a biggie. However, since it's being used for validation here, `[0-9]` is definitely way to go in my opinion.	[reply] [d/l]
Re^3: Using grep on windows by Bloodnok (Vicar) on Oct 27, 2009 at 17:40 UTC
\d and 0-9 are not equivalent - you sure of that ? From Using character classes we see: \d is a digit and represents 1. 0-9 A user level that continues to overstate my experience :-))	[reply]
Re^4: Using grep on windows by ikegami (Patriarch) on Oct 27, 2009 at 17:45 UTC
\d matches a digit. There are more digits than 0,1,2,3,4,5,6,7,8,9. `$ perl -Mcharnames=:full -le'print "\N{BENGALI DIGIT ZERO}" =~ /^\d\z/ + \|\| 0' 1` [download] The same thing, written differently: `$ perl -le'print chr(0x09E6) =~ /^\d\z/ \|\| 0' 1` [download]	[reply] [d/l] [select]