Re: problems dereferencing an array of arrays as a hash value

How about a new array reference, like this?

case /packetclassifierlist/    { $tlvHash{pktClassList} = [ @pktClassL
+ist ] }
[download]

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Re^2: problems dereferencing an array of arrays as a hash value by jasonl (Acolyte) on Nov 23, 2009 at 17:14 UTC
Thanks! That did it, but I'm not quite clear why. Can you explain a little what's going on there?	[reply]
Re^3: problems dereferencing an array of arrays as a hash value by gmargo (Hermit) on Nov 23, 2009 at 17:42 UTC
The brackets `[]` create a reference to an anonymous array. With an array inside the brackets like `[ @pktClassList ]`, the contents of the `@pktClassList` array are copied into the new anonymous array. There is a different way to get the same effect, but which avoids the second copy. If the `@pktClassList` array is a local variable in a subroutine, which gets used only once before going out of scope, then you could have used the `@pktClassList` array directly like this: `case /packetclassifierlist/ { $tlvHash{pktClassList} = \@pktClassLi +st }` [download] The key is the scope of the original `@pktClassList` array - when the variable goes out of scope, it becomes an anonymous array by virtue of being referenced by the `%tlvHash` hash. Quite unlike the C language. See perlref for more info on references. Anonymous arrays are addressed early in the document.	[reply] [d/l] [select]