Getting the date of today as a number (was: Date question)

Anonymous Monk has asked for the wisdom of the Perl Monks concerning the following question:

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Re: Getting the date of today as a number (was: Date question) by chromatic (Archbishop) on Apr 20, 2000 at 04:11 UTC
Today's day: `my @time = localtime(); print $time[3]` [download] See localtime for details.	[reply] [d/l]
RE: Getting the date of today as a number (was: Date question) by Simplicus (Monk) on Apr 20, 2000 at 04:24 UTC
The localtime(time) function returns a nine element array, the values of the array are: index value ===================== [0] second [1] minute [2] hour [3] month day [4] month [5] year [6] day of week [7] day of year [8] isdst : not sure what this refers to . . . There are a couple of things to watch out for in this array . . .the elements month and day are zero-based (because you'll probably use them as indexes into arrays containing month and day names . . .) and the year element has had 1900 subtracted from it, so this code: `@timearray = localtime(time); print "$timearray[5]\n"` [download] will print 100, not 00 or 2000. Good question! Simplicus	[reply] [d/l]
RE: RE: Getting the date of today as a number (was: Date question) by Simplicus (Monk) on Apr 20, 2000 at 06:47 UTC
Sorry, but the above writeup has a couple flaws, and thanks to chromatic for setting me straight. First, the $isdst scalar is a flag for daylight savings time, 1 for yes, 0 for no, and negative is "unknown." Second, the year hasn't really had 1900 subtracted from it, it's really just the number of years since 1900. Thanks again to my Dodecatonic friend, chromatic. (I was a music composition major, once upon a time.)	[reply]
Re: Getting the date of today as a number (was: Date question) by dsdisc (Initiate) on Apr 20, 2000 at 04:01 UTC
The simplest way would be to print: `print scalar(localtime(time));` [download] Although you could format it by getting all the elements individually: `@elements = localtime(time);` [download] You can easily find a reference that will tell you what each element is, just remember that months, days of year, other data is 0 based - meaning January is 0, Feb is 1, .. Dec is 11.	[reply] [d/l] [select]
Re: Getting the date of today as a number (was: Date question) by btrott (Parson) on Apr 20, 2000 at 05:31 UTC
Or one other way, just for fun, and because I like the fact that it's way easy to remember: `use Time::localtime; my $lt = localtime; print "Today's day of the month is ", $lt->mday;` [download] perldoc Time::localtime for more details.	[reply] [d/l]
RE: Getting the date of today as a number (was: Date question) by Anonymous Monk on Apr 20, 2000 at 21:47 UTC
`print (localtime())[4];`	[reply] [d/l]
Re^2: Getting the date of today as a number (was: Date question) by Persib (Acolyte) on May 22, 2007 at 10:39 UTC
i tried yours, not working.. then i modified yours so it looks like `perl -e 'print ((localtime)[5])'` [download] and its work. zak	[reply] [d/l]