Re: calling a sub routine from a scalar

&{$exception->{action}}(args); should do fine

Update You can also do

local(*foo) = \&{$exception->{action}};
&foo(args);
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if you want, temprarily globbing your subroutine ref to the name foo... either way works...

Update2 My bad, just realized I needed \ in front of &{$exception->{action}}; to make it work... all fixed
- Ant

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Re: Re: calling a sub routine from a scalar by cmilfo (Hermit) on May 16, 2001 at 21:06 UTC
Actually, the problem with this is `$exception->{action}` cannot be dereferenced, as it is a string.	[reply] [d/l]
Re: Re: Re: calling a sub routine from a scalar by suaveant (Parson) on May 16, 2001 at 22:04 UTC
but perl can call a subroutine by name from a string, or a variable, if you do ${'foo'}, perl sees a string so tries to look at the value of $foo. Same thing goes for subroutines... slower, but very handy. - Ant	[reply]