You can. The way you showed it flattens the array, if you don't want that, put a reference to it in your data structure:

my $value = {
 'key' => ['value', \@array, 'add'];
}
[download]

See also: perllol, perldsc, perlreftut.

I like the way that moritz answered. The answer will work great for this specific single question! But I am not sure that the answer will help you in your application.

my @array = ('test', 'demo', 'work');
my $value = 
    {
       'key' => ['value', \@array, 'add'];
    }
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This puts a reference to @array as the 2nd thing in the anon list that 'key' points to. If the contents of @array can vary and in real application, I presume that it will, then,

'key' => ['value', [@array], 'add'];
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The above says that I am going to make copy of @array, and then assign a reference to that in this key structure. That is different than assigning a ref to the @array.

Is it possible?

>perl -wMstrict -le
"use Data::Dumper;
 my @array = qw(test demo work);
 my $value = {
   'key' => ['value', @array, 'add']
   };
 print Dumper $value;
"
$VAR1 = {
          'key' => [
                     'value',
                     'test',
                     'demo',
                     'work',
                     'add'
                   ]
        };
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use Data::Dumper;
my @array = ('test', 'demo', 'work');

my $hashref = {'key'=>['value', [@array], 'add']};

push @{$hashref->{'key'}->[1]}, 'home';
push @{$hashref->{'key'}->[1]}, 'cars';

printf "I popped \'%s\'.\n\n", pop @{$hashref->{'key'}->[1]};
print Dumper(\%$hashref);
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