Re: Syntax question: Method call, where method name is calculated from an expression

Yes, using the reference/dereference trick:

$object->${\method()}(@args);
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Here, method() is called, a reference to the result is taken through the backslash, and that reference is de-referenced via ${ }. The resulting method is called on behalf of $object, passing along @args.

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Re^2: Syntax question: Method call, where method name is calculated from an expression by rovf (Priest) on Dec 04, 2009 at 15:52 UTC
Thank you! This works! -- Ronald Fischer <ynnor@mm.st>	[reply] [d/l]