Re: Boolean counter?

The xor operator will do what you want:

$counter = $counter xor 1
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$counter ^= 1
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(tested with perl -wle "print $counter ^=1 for 1..3")

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Re^2: Boolean counter? by doug (Pilgrim) on Dec 07, 2009 at 18:22 UTC
I agree that the XOR solution is perfectly correct, but why use that instead of NOT? Isn't `$counter = ! $counter;` easier to read? That said, I have to admit that I like the snazzyness of the in place ^= syntax. It is hard to get more concise than that. - doug	[reply] [d/l]
Re^3: Boolean counter? by ikegami (Patriarch) on Dec 07, 2009 at 18:37 UTC
The difference is that `$toggle ^= 1;` leaves you with a number (0 or 1) while `$toggle = !$toggle;` leaves you with a boolean. Honestly, it sounds like the OP wants a boolean, so the easier to read negation should be used. If he wants to display the boolean, that's an outputting formatting issue to be resolved then.	[reply] [d/l] [select]