Re^4: Boolean counter?

$i appears only once, the behaviour is defined

$ perl -MO=Deparse,-p -le"print - --$i"
BEGIN { $/ = "\n"; $\ = "\n"; }
print((-(--$i)));
-e syntax OK
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You were thinking of

print(-( ++$i - --$i ))
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Re^5: Boolean counter? by ikegami (Patriarch) on Dec 07, 2009 at 17:01 UTC
While the operand evaluation order for the ops you've used in your example isn't defined, it doesn't matter (unless there's an overflow) for that example. It's just a clarity issue. $i appears only once, the behaviour is defined Except it (`$Counter`) appeared twice.	[reply] [d/l]