in reply to regular expression help

I agree with previous replies that there is no point to using a 'one big regex' solution when the job can be done more clearly, even if with more statements.

That said, I could not understand why the  $match2 regex would not extract the  b named capture from  $input1 string: there is clearly a  'b=2' substring there to  b extracted.

A little instrumentation made the situation clear. The first  /.*?/ lazy expression and the  /(?<b>b=(\d))?/ lazy capture are immediately satisfied. That leaves the second  /.*?/ lazy expression and the final required expression at the end of the line to match. The second  /.*?/ tries to match with nothing, but then must backtrack (forward-track?) and consume all text (including the  'b=2' substring) until the final required expression matches in order to achieve an overall match.

This is made clear in the following (note the added named capture around the second  /.*?/):

>perl -wMstrict -le "my $input1 = 'a=1 gibberish b=2 c=3'; my $match2 = '^(?<a>a=(\d)).*?(?<b>b=(\d))?(?<gib>.*?)(?<c>c=(\d))$'; print qq{input1 '$input1'}; print qq{Using regex $match2}; if ($input1 =~ m/$match2/){ print qq{a '$+{a}' b '$+{b}' c '$+{c}' gib '$+{gib}'}; } else { print qq{Input1: didn't match}; } " input1 'a=1 gibberish b=2 c=3' Using regex ^(?<a>a=(\d)).*?(?<b>b=(\d))?(?<gib>.*?)(?<c>c=(\d))$ Use of uninitialized value in concatenation (.) or string at ... a 'a=1' b '' c 'c=3' gib ' gibberish b=2 '