>>Just as a point of observation, the double-e means to double evaluate, correct? In the first pass, this would convert $1 to the equivalent string '$var' and then on the second pass, evaluate it to the value of $var. >>

That is exactly right. You can put as many /e modifiers as you want, and it will be evaluated that many times.

To solve the problem, you basically have two choices (well, I can think of two, there are probablly more), multiple /e modifiers or symbolic references. Personally, I think that the double-e approach is a bit cleaner than using symbolic references.

The 15 year old, freshman programmer,
Stephen Rawls