in reply to Replacing a given character starting with the xth occurence in a string

Here's another way that avoids a lot of fuss. It's rather like quent's but avoids
unneeded churning on the counter.

It also works with multicharacter substitutions and, with some odd results unless
the start count < 1, the target can be a regex.

#!/usr/bin/perl -w # -*-Perl-*- use strict; sub zaxo { my ($str,$chr,$new,$nbr)=@_; $str=~s/$chr/(--$nbr>0)?$chr:$new/geo; $str; } my $s = "Terence and Philip are sweet\n"; my $c = 'e'; my $r = 1; my $n = 3; print zaxo( $s,$c,$r,$n); exit;
Against the bbfu benchmark posted above (corrected &mine output) I get:
Benchmark: timing 500000 iterations of BBFU'S, MINE, Quent's, Zaxo's.. +.<BR/> BBFU'S: 12 wallclock secs (12.18 usr + 0.05 sys = 12.23 CPU) MINE: 13 wallclock secs (12.32 usr + 0.06 sys = 12.38 CPU) Quent's: 13 wallclock secs (13.40 usr + 0.03 sys = 13.43 CPU) Zaxo's: 10 wallclock secs (10.59 usr + 0.00 sys = 10.59 CPU)

I must to agree with MeowChow that this is a litmussy kind of question.

After Compline,
Zaxo