Re^4: Date conversion in perl?

ww@GIG:~$ perl -wle 'print scalar(localtime(20100302165019));'
Wed Dec 31 18:59:59 1969

ww@GIG:~$ perl -wle 'print scalar(localtime(20100302165219));'
Wed Dec 31 18:59:59 1969                               ^

ww@GIG:~$ perl -wle 'print scalar(localtime(20100305165219));'
Wed Dec 31 18:59:59 1969                           ^

ww@GIG:~$ perl -wle 'print scalar(localtime(23100305165219));'
Wed Dec 31 18:59:59 1969                     ^
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32bit 5.10 Linux

Comment on Re^4: Date conversion in perl? Download Code

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Re^5: Date conversion in perl? by bart (Canon) on Mar 03, 2010 at 14:11 UTC
FYI that date, 1 second before epoch, corresponds with a time value -1 (hex FFFFFFFF) which is commonly used as an overflow value for integer arithmetic.	[reply]
Re^5: Date conversion in perl? by ikegami (Patriarch) on Mar 03, 2010 at 15:59 UTC
It's a different failure mode, but it's still failing by returning the date for -1 instead of returning undef. I imagine that some of the work in this area is done by the underlying C library, so you can expect differences between systems. I believe that might also be changed in 5.12 to avoid the year 2038 overflow. Update: Confirmed: `$ /usr/bin/perl -le'print scalar localtime "201003031234"' Wed Dec 31 18:59:59 1969 $ ./perl -le'print scalar localtime "201003031234"' Fri Jul 14 19:20:34 8339` [download]	[reply] [d/l]