in reply to Recursive substitution difficulties
s{(<name>.*?</name>)<value>(.*?)</value>}{ $1 . join '', map "<value>$_</value>", split /\|/, $2 }seg;
Better version for 5.10+:
s{<name>.*?</name>\K<value>(.*?)</value>}{ join '', map "<value>$_</value>", split /\|/, $1 }seg;
Update: Oops, didn't pay enough attn to the desired output.
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