Re: setting multidimensional array values

the 'x' operator is only going to work to give you strings. However, here's a time where I've found map to be very useful:

@{$array[$i]} = map {0} (1..3);
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Re: Re: setting multidimensional array values by da (Friar) on May 24, 2001 at 19:58 UTC
For those who, like me, were puzzled about the idea of using 'x' in a list context, check out the 'perlop' manpage: Binary "x" is the repetition operator. In scalar context, it returns a string consisting of the left operand repeated the number of times specified by the right operand. In list context, if the left operand is a list in parentheses, it repeats the list. `@ones = (1) x 80; # a list of 80 1's @ones = (5) x @ones; # set all elements to 5` [download] `--- -DA` [download]	[reply] [d/l] [select]

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Re: Re: setting multidimensional array values
by da (Friar) on May 24, 2001 at 19:58 UTC

Binary "x" is the repetition operator. In scalar context, it returns a string consisting of the left operand repeated the number of times specified by the right operand. In list context, if the left operand is a list in parentheses, it repeats the list.

           @ones = (1) x 80;           # a list of 80 1's
           @ones = (5) x @ones;        # set all elements to 5
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-DA
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