@ printing content of referenced array

siddheshsawant has asked for the wisdom of the Perl Monks concerning the following question:

Hello monks, I was trying to print the contents of array which was referenced.The code is given below

$desc_ref = \@description."\n";

print"Description =".$$desc_ref[$i]."\n";
[download]

And I am getting empty array as a output.Kindly let me know how to print contents of the array @description in this case

Thanks in advance !!!

Comment on @ printing content of referenced array Download Code

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Re: printing content of referenced array by ikegami (Patriarch) on Mar 23, 2010 at 17:40 UTC
Start by using `use strict; use warnings;`. It'll point out that `$desc_ref` doesn't contain a reference. (`."\n"`???)	[reply] [d/l] [select]
Re: @ printing content of referenced array by toolic (Bishop) on Mar 23, 2010 at 17:42 UTC
$desc_ref = \@description."\n"; Get rid of the newline: `$desc_ref = \@description;` [download] Data::Dumper is extremely helpful: `use Data::Dumper; print Dumper($desc_ref);` [download]	[reply] [d/l] [select]
Re: @ printing content of referenced array by 7stud (Deacon) on Mar 23, 2010 at 18:03 UTC
Did you take a wrong turn somewhere? This isn't a php forum, it's a perl forum. `use strict; use warnings; use 5.010; my @numbers = (10, 20, 30); say "The numbers are: @numbers"; #The numbers are: 10 20 30 my $aref = \@numbers; say "The numbers are: @$aref"; #The numbers are: 10 20 30 say "One number is: @$aref[0]"; #10 say "Another number is: " . $aref->[2]; #30` [download]	[reply] [d/l]
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