Re^2: Dereferencing a hash ref in an array ref

I just meant that the dereferencing using for the array deref the curly brackets, and for the hash deref the dereferencing using the arrow syntax. I thought its better only to use the second one, but dont know how that have to look like.

Part 1:

@{$hashref}

Part 2 ("$hashref"):

$sth->{NAME_uc}

If thats already "pretty" (one syntax style for dereferencing) my thoughts just were wrong, would be an answer too.

Greetings, Schaelle

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Re^3: Dereferencing a hash ref in an array ref by Anonymous Monk on Mar 26, 2010 at 08:38 UTC
:) `use Anonymous::Monk; no ESP;` References quick reference You can only get scalars using the arrow syntax, you cant get multiple values `my $sth = { NAME_uc => [ 1 .. 2 ] }; print join "\n" , $sth->{NAME_uc}[0 ,1 ]; __END__ 2` [download] `my $sth = { NAME_uc => [ 1 .. 2 ] }; print join "\n" , @$sth->{NAME_uc}[0 ,1 ]; __END__ Not an ARRAY reference at - line 3.` [download] That is why you need curlies `my $sth = { NAME_uc => [ 1 .. 2 ] }; print join "\n" , @{ $sth->{NAME_uc} } [0 ,1 ]; __END__ 1 2` [download] The arrow-less way `my $sth = { NAME_uc => [ 1 .. 2 ] }; print join "\n" , @{ $$sth{NAME_uc} } ,'' __END__ 1 2` [download] References quick reference	[reply] [d/l] [select]

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Re^3: Dereferencing a hash ref in an array ref
by Anonymous Monk on Mar 26, 2010 at 08:38 UTC

use Anonymous::Monk; no ESP;

References quick reference

You can only get scalars using the arrow syntax, you cant get multiple values

my $sth = { NAME_uc => [ 1 .. 2 ] };
print join "\n" , $sth->{NAME_uc}[0 ,1 ];
__END__
2
[download]

my $sth = { NAME_uc => [ 1 .. 2 ] };
print join "\n" , @$sth->{NAME_uc}[0 ,1 ];
__END__
Not an ARRAY reference at - line 3.
[download]

my $sth = { NAME_uc => [ 1 .. 2 ] };
print join "\n" , @{ $sth->{NAME_uc} } [0 ,1 ];
__END__
1
2
[download]

my $sth = { NAME_uc => [ 1 .. 2 ] };
print join "\n" , @{ $$sth{NAME_uc} } ,''
__END__
1
2
[download]

References quick reference

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