The scope in which the variable exists ceases to exist long before the function was called. The function definitely references an out-of-scope variable.

Yes. What's your point here? I don't think I claimed the function doesn't.

Let me requote doug:

Any block that creates scoped variables is a closure in my book.

And the block discussed here is the following posted by rovf:

{ # closure starts here
  my $shared_variable;
  sub ref_test1 { ... }
  sub ref_test2 { ... }
}
[download]

Or are you going to retract your retraction about the outer block being a closure?

You seem to think nesting a named sub is the same as nesting blocks

Where did you get that idea from? Why does that even matter in my argument with doug that a closure is something else than just a block giving scope to a variable?