in reply to Re^5: Referencing in Function not working correctly.
in thread Referencing in Function not working correctly.

I am sorry I have no idea what that does. Please explain. My guess is @x[0]=z, @y[0]=y and @z[0]=z.

When I had the below statement, I was trying to create and initialize values of all variables.

my (%Aseen, %Bseen, %count, @isec, @diff, @union, @aonly) = ();

Please let me know what I'm doing wrong.

Thanks for your help.
  • Comment on Re^6: Referencing in Function not working correctly.

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Re^7: Referencing in Function not working correctly.
by Your Mother (Archbishop) on Apr 02, 2010 at 20:01 UTC

    :)

    perl -MData::Dumper -lwe 'my ( @x, @y, @z ) = ("z", "y", "z"); print D
+umper(\(@x,@y,@z))'
$VAR1 = [
          'z',
          'y',
          'z'
        ];
$VAR2 = [];
$VAR3 = [];

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    my (%Aseen, %Bseen, %count, @isec, @diff, @union, @aonly);

    They all are declared empty. No need to be explicit about it; and as the example above shows, that form of being explicit won't do what you might think anyway.

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Re^7: Referencing in Function not working correctly.
by jwkrahn (Abbot) on Apr 02, 2010 at 20:03 UTC

    When you have an aggregate (array or hash) in a list that variable will be assigned all the values.    So: 

    my ( @x, @y, @z ) = ("z", "y", "z");

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    Is exactly the same as: 

    my @x = ("z", "y", "z");
my ( @y, @z );

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      So, I don't get what is wrong with me doing

      (%count, @isec, @diff, @union, @aonly) = ();

      to initialize?

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        Because @isec, @diff, @union and @aonly will not be effected by that assignment but you seem to think that they will.

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