Re^3: Top and bottom 10 percent elements of an array

Good point. Also, the last two solutions do not work well if the number of array elements are odd. For instance, if we have 11 unique numbers it 5 should be A, 5 B and 1 dash. But both of them print 6 "A"s and 4 "B"s and no dash. I tried to play around with the ranges but could not resolve it. I think 50% is the maximum that we want to go to be able to divide the population of numbers into two categories. Therefore, I am not worry about 75% or higher unless there is another use for this little script.

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Re^4: Top and bottom 10 percent elements of an array by ikegami (Patriarch) on Apr 29, 2010 at 18:36 UTC
My solution didn't have a problem with 50% of 11 per say. My solution always gave the wrong answer. (The OP confused me by saying 10% should give `B - B - - - - A A -` when that's the output for 20%.) Fixed. `my $portion = 0.50; my @array = (1..11); B B B B B - A A A A A` [download] Same goes for codeacrobat's answer.	[reply] [d/l] [select]