Although you've asked the user how many numbers to enter up front, and stored it in $times, you then make no use it at all.

So when you do @ascii=<STDIN>;, perl doesn't know how many numbers to ask for, so It'll just keep asking for more until the user does something to stop it. For example, typing ^Z (or ^D on *nix?). But if the user enters more or less numbers before doing that, your program will get more or less than it is expecting.

You need to modify your code so that it uses the value of $times to control how many times you ask the user for another number. Eg.

#!/usr/bin/perl 
use strict;
use warnings;

print "Enter the number of times : "; 

my $times=<STDIN>; 

my @ascii;

foreach (1 .. $times ) { 
    push @ascii, scalar <STDIN>; 
}

foreach my $s ( @ascii ) {
    print chr($s); 
}
[download]

You'll get on much better if you format your code properly. And using strict and warnings will save you many hours of reshaping your plaster with your forehead.

The OP said:

concatenates the corresponding characters to form a string

So this may be better:

my $ascii;

foreach ( 1 .. $times ) {
    $ascii .= chr <STDIN>;
}

print $ascii;
[download]

Thanks to everyone here for replying.

My solution was reading number of times in a variable called $times and then loop to read or print.

If you read exam test solution as mentioned above, it read the input different way. For example @ascii is an array :

$ascii[0]=3;  (which mean read input 3 times)
$ascii[1]=65; (read first input)
$ascii[2]=66; (read second input)
$ascii[3]=66; (read third input)
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Here automatically ends without pressing Ctrl+Z/D because as said first value ascii as number of times to read input.

This is what I understand from the problem, please tell me if you have another solutions that can execute this task.

Thanks to all. Iam a new comer to perl monks.

Maybe you want to tell us what the problem with your solution is? Identifying the problem with what you have currently is the first step towards finding ways how to fix this.

@ascill
     ^^

#!/usr/bin/perl 

use strict;
use warnings;

print "Enter the number of times : "; 

my $times= <STDIN>; 

my $prompt = q{Add values : };
my $maskPrompt = "\r" . ' ' x  (length($prompt) + 2) . "\r";
my (@input) = ();
print $prompt;

chomp @input;
print do {
     local $" =  "\n  -->";
     "  -->@input"
}, "\n";
   
my $ascii;
foreach $times(1 .. $times) { 
    $ascii .= chr (<STDIN>);
}
print $ascii, "\n";
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#!/usr/bin/perl 

use strict;
use warnings;

print "Enter the number of times : "; 

my $times= <STDIN>; 

my $prompt = "Add values : ";
$prompt = "\r" . ' ' x  (length($prompt) +2) . "\r";
print $prompt;
   
my $ascii;
foreach (1 .. $times) { 
    $ascii .= chr (<STDIN>);
}
print $ascii, "\n";
[download]

my $maskPrompt = "\r" . ' ' x  (length($prompt) + 2) . "\r";
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Why do you create this variable if you never use it?

my (@input) = ();
print $prompt;

chomp @input;
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Why do you assign nothing to an already empty variable?    And why then do you chomp an empty variable?

foreach $times(1 .. $times) { 
    $ascii .= chr (<STDIN>);
}
[download]

Why are you using the same variable name for the loop creation and for the local variable?    I have been using Perl for many many years and I have never seen anyone do this before and it is very confusing.    It only works because the value stored in $times is local to the loop body but it is not something that you should do because it is very confusing.

I completely agree with you(jwkrahn) using the same variable name for the loop creation and even i never see such questions in my life. Believe me, all 10 questions which i was attempting to get Perl Certification from Expert Ratings has the same form of reading the input. I attempted test two times but failed.

http://www.expertrating.com/certifications/PERL-Programming-Skills-Test.asp

During this test, i tried to represent the code test several ways but nothing works.

Thanks.