Re^4: passing array ref without variable

No I do not want to pass a hash. What I want to do is having a hash ($h{key} = value) and

sub my_function 
{
my $arr_ref = shift;
...
}
[download]

I can pass keys as an array ref by

my_function([keys %hash])
[download]

Now, I want to pass values as an array ref in a shortest way without forming an array. Is it possible?

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Re^5: passing array ref without variable by FunkyMonk (Bishop) on May 03, 2010 at 21:15 UTC
Hmmm. You know that you get the keys of a hash using a function called keys. What do you think would be the name of the function that returns the values of a hash?	[reply]
Re^5: passing array ref without variable by LanX (Saint) on May 03, 2010 at 21:26 UTC
Is it possible? Short answer, yes! `my_function([values %hash])` but please be aware that this is only a flat copy. Cheers Rolf	[reply] [d/l]
Re^6: passing array ref without variable by Anonymous Monk on May 04, 2010 at 00:50 UTC
what is a "flat copy?"	[reply]
Re^7: passing array ref without variable by LanX (Saint) on May 04, 2010 at 06:26 UTC
aka "shallow copy" let me google for you: flat copy perl http://www.stonehenge.com/merlyn/UnixReview/col30.html Shallow vs deep copy (Was Re^3: hash ref mind blow) Cheers Rolf	[reply]
Re^8: passing array ref without variable by Anonymous Monk on May 04, 2010 at 06:36 UTC
Re^9: passing array ref without variable by LanX (Saint) on May 04, 2010 at 06:44 UTC