in reply to Re^2: conditional expression testing
in thread conditional expression testing
m#^(hana)(bbs)?(?(1)\2\1|\1)$#;
is the same as
m#^(hana)(bbs)?\2\1$#;
since (?(1)...) is always true. And since you don't use the captures, that can be be simplified to
m#^hana(?:bbsbbs)?hana$#;
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