Re^4: Noob OO Question

$$self->{test_b}->() first dereferences $self. Writing $self->{test_b}->() should work. Or without arrows: &{$$self{test_b}}(). Note the placement of the outer parens.

Also, how do I dereference '$test->method_d()'?

You don't. $test->method_d() returns a string.

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Re^5: Noob OO Question by Anonymous Monk on Jun 08, 2010 at 00:12 UTC
Typing it like this doesn't work for me. `$self->{test_b}->()` [download] It gives me this output. `Not a CODE reference at Hi.pm` [download]	[reply] [d/l] [select]
Re^6: Noob OO Question by ikegami (Patriarch) on Jun 08, 2010 at 04:59 UTC
Better yet, change `my $test = new Hi( test_a => 'hello', test_b => \sub{ return 1 }, test_c => \sub{ get_me( $get_a, $get_b ) }, );` [download] to `my $test = new Hi( test_a => 'hello', test_b => sub{ return 1 }, test_c => sub{ get_me( $get_a, $get_b ) }, );` [download] There's no reason for the extra level of indirect.	[reply] [d/l] [select]
Re^6: Noob OO Question by bluescreen (Friar) on Jun 08, 2010 at 00:21 UTC
Try this: `${$self->{test_b}}->();` [download]	[reply] [d/l]