There is no generic loop structure that just skips the first element. You can however use loop control like next to skip undesirable elements:

my $skip = 0;
for my $i (0 .. $#array) {
    next if $i == $skip;
    #process
}
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You can also you array slices in order to feed restricted sections of your array to a foreach loop:

for (@array[1 .. $#array]) {
    #process
}
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or if you have no need for the loop itself, you can use the slice with a direct assignment:

my @new_array = @array[1 .. $#array]; or if you meant skipping $array[1]

my @new_array = @array[0, 2 .. $#array];

You can do more advanced list preprocessing with map and grep. After all, TIMTOWTDI.

Do you want all elements of the array at once? Then use @array. Or do you want to process each element of the array? Then use

foreach my $element (@array) {
    print "I am processing the element '$element'\n";
};
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You might want to see perlsyn.

Further reading would be map if you want to transform elements of one array into another list.

for ($i = 1; $i < 10; $i++) {
   print $array[$i];
}
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Do you mean something like this?

for my $element ( @array ) {
    print $element . "\n";
}
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You can shift the first element off the array.

my $first_element = shift @array;
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gogoglou:

You can use the slice syntax to get a set of array elements:

my @array = (0 .. 50);
my @first5 = @array[0..4];
my @allButFirst = @array[1..$#array];
my @FirstThirdAndEighth = @array[0,2,7];
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For details, read perldoc perldata and look for "slice" to find information about array and hash slicing.

...roboticus