Re: Explaining a Regular Expression

It's an expression which always matches, i.e. the else branch won't be executed. UPDATE: What I have written, was non-sense. I should have said: It is an expression which matches iff the line contains only white space.

--
Ronald Fischer <ynnor@mm.st>

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Re^2: Explaining a Regular Expression by Fletch (Bishop) on Jul 06, 2010 at 15:18 UTC
`$ perl -le '$_ = "blort";if (/^\s*$/) { print "always matches" } else +{ print "Orly?" }' Orly?` [download] The cake is a lie. The cake is a lie. The cake is a lie.	[reply] [d/l]
Re^2: Explaining a Regular Expression by zek152 (Pilgrim) on Jul 06, 2010 at 15:14 UTC
This expression does not always match. The presence of `^` and `$` impose conditions that cause it to not always match. The code below shows a simple case which does not match `$data = "This doesn't match\n"; if ($data =~ /^\s*$/) { print "$data Matches\n"; } else { print "$data Does not match\n"; } #OUTPUT #This doesn't match # Does not match` [download]	[reply] [d/l] [select]
Re^3: Explaining a Regular Expression by rovf (Priest) on Jul 06, 2010 at 15:19 UTC
Sorry, this was probably the most stupid answer I have ever given in this forum. I should have looked closer - will update my node. -- Ronald Fischer <ynnor@mm.st>	[reply] [d/l]