Re^3: find one by one occurances

Why do you try s/.../identify_year($1)/ge? What is that supposed to do? I thought your objective was to identify a year and the surrounding words?

If you want to know whether there is one or more occurrence of a regular expression, you can use the following idiom:

my $var = "This is the year 2000.";
my @matches = ($var =~ /([0-9]{4})/g);
[download]

The regular expression I gave will only find four digits. You will need to modify that regular expression to also recognize two words before that year and two words after that year.

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Re^4: find one by one occurances by Selvakumar (Scribe) on Jul 23, 2010 at 07:11 UTC
that's the question i was raised here. How to modify the regular expression to find consecutive 5 words which the center word has year. if i use some thing like below `#$var=~s/(\w?) (\w?) ([0-9]{4}+[a-zA-Z]?) (\w?) (\w?)/&identify_year($ +1.$2.$3.$4.$5)/ge;` [download] it's not giving my required output and it fails here. "b1990 and 2000." U.S. etc., if u try. read my all questions clearly the year can occurs in any format not only 4 digits.	[reply] [d/l]
Re^5: find one by one occurances by Corion (Patriarch) on Jul 23, 2010 at 07:26 UTC
That is what you have to do. See perlretut and/or perlre. This is not a code writing service where we will write code for you. Maybe you might be interested in that `/\w?/` will only match zero or one "word character". If you want to match one or more, you might want to use `\w+`. Again, now is a good time to learn about regular expressions.	[reply] [d/l] [select]