in reply to Perl 6, defining a hash with interpolated string

I'm not really sure, but it seems that the colon is effectively ignored in that context. Try the following: 
use v6; 

my $item = :[:[:[$hkey]]];
say $item.perl;           # outputs [[["somekey"]]]

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Re^2: Perl 6, defining a hash with interpolated string
by Mr_Micawber (Beadle) on Aug 04, 2010 at 19:12 UTC

    I think I was looking for the interpolating analog of this model for specifying a literal hash pair:

    %kv = :LiteralKey<LiteralValue>

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      The last two of the following examples give you interpolation, but it is more of the "normal" interpolation you would expect in Perl. 
      use v6;


my %kv1 = :LiteralKey<LiteralValue>;

say :%kv1.perl;



my %kv2 = <LiteralKey>,<LiteralValue>;

say :%kv2.perl;



my $var3 = 'Literal';
my %kv3  = "{$var3}key",'LiteralValue';

say :%kv3.perl;



my $var4 = 'LiteralKey';
my %kv4  = "$var4",'LiteralValue';

say :%kv4.perl;

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      gives you 
      "kv1" => {"LiteralKey" => "LiteralValue"}
"kv2" => {"LiteralKey" => "LiteralValue"}
"kv3" => {"Literalkey" => "LiteralValue"}
"kv4" => {"LiteralKey" => "LiteralValue"}

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        I noticed playing with this code that the output of .perl differs depending on if the colon is in front of the variable:

        say :%kv4.perl; #"kv1" => {"LiteralKey" => "LiteralValue"}
say %kv4.perl;  #{"LiteralKey" => "LiteralValue"}

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        the colon seems to be plucking the Hash's name and creating a Pair with it.

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