Re: is this a regexp question ?

I'm not sure whether you can eval a function in a regex. If I understand your question correctly, you can just do


sub search_equivalent{
   #do stuff here and return your equivalent pattern
   return $equivalent;
}

my $equiv = search_equivalent();
if ($thisstring =~ m/$equiv/){
   ....
}
[download]

There is no real need to put a function call in the regex.

Jorg

"Do or do not, there is no try" -- Yoda

Comment on Re: is this a regexp question ? Download Code

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(ar0n) Re (2): is this a regexp question ? by ar0n (Priest) on Jun 04, 2001 at 05:14 UTC
Even though this is probably not what he meant, you can call a function from within a code-block within a regex: `$foo =~ /(?{match_foo()})/;` [download] [ ar0n ]	[reply] [d/l]