in reply to pass perl variable to shell script

Use command substitution in the shell, e.g.

#!/bin/sh

output=$(perl -e 'print "hello world"');

echo $output;

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If you have a more complex Perl-script then I would put it in it's own file and call it via $(perl script.pl) rathern then embedding it directly in the shell-script as a lot of metacharacters that Perl uses are also special to the shell and escaping all of them properly is a mess.

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Re^2: pass perl variable to shell script
by arthurs (Novice) on Aug 11, 2010 at 15:38 UTC
    Thanks, morgon. But the command substitution will not work for me here. The code snippet I have is just an example to get my point across on how I can access a variable (str3 in this case) in shell after I set it in Perl.
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      The command substuition captures the output of the perl-script at the shell-side.

      So if you only have to pass one value you simply print it to standard output in Perl.

      #in perl-script "script.pl"
print $variable;

#in the shell-script:
variable=$(perl script.pl)
echo $variable

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      If you must pass more than one variable you e.g. print them in a certain format "$var1=$var2=$var3" and parse that on the shell side.
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[d/l]
        morgon, I only have one script -- shell script, in which i have a block of perl code. Lets forget I have 'print' statement in the perl block. Lets say I am setting str3 somewhere in the middle of the perl block. After perl block has finished executing, I am back in the shell part of the code and need to get the content of str3 variable that was set in the perl block of the code. How do I do it?
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