Re^2: Getting around "/" as a word boundary

Hi ikegami, I am a perl beginner, I don't get the following regex very much. Can you explain the (?<!/) part in detail? Thanks in advance.

$doc2=~s#(?<!/)\b($_)\b#$1/$hashstore{uc($_)}#ig;

Comment on Re^2: Getting around "/" as a word boundary Download Code

Replies are listed 'Best First'.
Re^3: Getting around "/" as a word boundary by AnomalousMonk (Archbishop) on Aug 12, 2010 at 08:48 UTC
This is a "zero-width, look-behind assertion". The assertion is true if `(?<!/)` does not immediately follow a '/' (forward slash) character at the point at which the assertion occurs in the regex. See `(?<!pattern)` in the Extended Patterns section (in the Look-Around Assertions subsection) of perlre. Update: Added "zero-width" to description.	[reply] [d/l] [select]
Re^3: Getting around "/" as a word boundary by ikegami (Patriarch) on Aug 12, 2010 at 16:14 UTC
"`(?<!/)`" means "not immediately preceded by '`/`'"	[reply] [d/l] [select]