I'm not actually sure why you need the @ at all. I believe that what you probably want is $data[$i]->{"whatever"}. It looks to me as though the poster thinks that the @ is needed because @data is and array (native php coder?). The use of ->{"something"} tells me that $data[$i] contains a hashref, not an array ref. Even if $data[$i] was an array ref, you'd only need the @ to either a. dereference the array, or b. use an array slice.

Yes, I am reasonably new to Perl, I am using Text::CSV::Slurp. The @ is used because $data is returned as a reference to an array of hashes, so:

@$data[0] -> {"data"}
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Returns the first hash inside data, and points to the value associated with the key "data". *unless my understanding is wrong*

If $data is a reference to an AoH, then the following is sufficient


perl -le '$data=[{ data => 1 },{a => 2, b => 3}];print $$data[0]->{dat
+a}'
1
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And if you try the below code, you can see the error u got,


 perl -wle '$data=[{ data => 1 },{a => 2, b => 3}];print $$data[1]->{c
+}'
Use of uninitialized value in print at -e line 1.
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see perldsc for details.

This is only an opinion, but:

I would rather keep to a single syntax for de-referencing when possible. As with most things in perl, there is more than one way to do it, and different ways have different strengths. In some cases using the @$arrayref; %$hashref; $$scalarref may be better, and in others $arrayref->[0]; $hashref->{key}; may be better. That having been said... @$data[$i]->{key} uses two different syntax's for de-referecing, in the same statement. I'd say that $data->[$i]{key} is much clearer.

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