Re: deferencing an hash in a subroutine

sub test {
    for (my $i = 0; $i < @_; $i += 2) {
        if ($_[$i] eq 'a') {
            $_[$i+1] = 'found a';
        }
    }
}

my $a = 'not found';

test b => 3, a => $a;
print "$a\n";
[download]

But beware, chaning your caller's arguments is evil, and usually produces code that's hard to understand and read.

Perl 6 - links to (nearly) everything that is Perl 6.

Comment on Re: deferencing an hash in a subroutine Download Code

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Re^2: deferencing an hash in a subroutine by saintex (Scribe) on Aug 20, 2010 at 15:13 UTC
and if I try to forse at the end of my sub: `$_[0]=\%q;` [download] It will overwrite the previous hash reference. is it correct?	[reply] [d/l]
Re^3: deferencing an hash in a subroutine by moritz (Cardinal) on Aug 20, 2010 at 15:19 UTC
`$_[0]=\%q;` sets the first argument on the caller side to `\%q`. Which only makes sense if you pass a scalar variable as first argument. Maybe it would be more helpful if you wrote what the underlying reason is for doing what you try to do. Maybe that way we can suggest a better solution. See also XY Problem. Perl 6 - links to (nearly) everything that is Perl 6.	[reply] [d/l] [select]
Re^4: deferencing an hash in a subroutine by saintex (Scribe) on Aug 20, 2010 at 16:28 UTC
ok, there is an update on my first post. thank you.	[reply]